Distance from Doctor Phillips to Bad Sassendorf
The shortest distance (air line) between Doctor Phillips and Bad Sassendorf is 4,690.31 mi (7,548.33 km).
How far is Doctor Phillips from Bad Sassendorf
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 12:19 (08.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 18:19 (08.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,690.31 miles which is equal to 7,548.33 km.
Doctor Phillips, Florida, United States
Related Distances from Doctor Phillips
Bad Sassendorf, Soest, Germany