Distance from Dent to San Lazzaro di Savena
The shortest distance (air line) between Dent and San Lazzaro di Savena is 4,657.06 mi (7,494.81 km).
How far is Dent from San Lazzaro di Savena
Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 09:49 (31.08.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 15:49 (31.08.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,657.06 miles which is equal to 7,494.81 km.
Related Distances from Dent
San Lazzaro di Savena, Bologna, Italy