Distance from Dent to Bad Sassendorf
The shortest distance (air line) between Dent and Bad Sassendorf is 4,275.31 mi (6,880.45 km).
How far is Dent from Bad Sassendorf
Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 20:34 (03.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 02:34 (04.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,275.31 miles which is equal to 6,880.45 km.
Related Distances from Dent
Bad Sassendorf, Soest, Germany