Distance from De Witt to Steenokkerzeel
The shortest distance (air line) between De Witt and Steenokkerzeel is 3,645.91 mi (5,867.52 km).
How far is De Witt from Steenokkerzeel
De Witt is located in New York, United States within 43° 1' 48" N -77° 55' 5.16" W (43.0300, -76.0819) coordinates. The local time in De Witt is 15:03 (19.07.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 21:03 (19.07.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,645.91 miles which is equal to 5,867.52 km.
De Witt, New York, United States
Related Distances from De Witt
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium