Distance from Davidson to San Pietro in Casale
The shortest distance (air line) between Davidson and San Pietro in Casale is 4,650.28 mi (7,483.90 km).
How far is Davidson from San Pietro in Casale
Davidson is located in North Carolina, United States within 35° 29' 2.4" N -81° 10' 31.08" W (35.4840, -80.8247) coordinates. The local time in Davidson is 01:53 (25.08.2025)
San Pietro in Casale is located in Bologna, Italy within 44° 42' 0" N 11° 24' 0" E (44.7000, 11.4000) coordinates. The local time in San Pietro in Casale is 07:53 (25.08.2025)
The calculated flying distance from San Pietro in Casale to San Pietro in Casale is 4,650.28 miles which is equal to 7,483.90 km.
Davidson, North Carolina, United States
Related Distances from Davidson
San Pietro in Casale, Bologna, Italy