Distance from Daphne to Aleksandrow Kujawski
The shortest distance (air line) between Daphne and Aleksandrow Kujawski is 5,185.20 mi (8,344.77 km).
How far is Daphne from Aleksandrow Kujawski
Daphne is located in Alabama, United States within 30° 37' 34.68" N -88° 7' 6.24" W (30.6263, -87.8816) coordinates. The local time in Daphne is 08:01 (28.08.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 15:01 (28.08.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,185.20 miles which is equal to 8,344.77 km.
Daphne, Alabama, United States
Related Distances from Daphne
Aleksandrow Kujawski, Włocławski, Poland