Distance from Czersk Pomorski to Susanville
The shortest distance (air line) between Czersk Pomorski and Susanville is 5,478.10 mi (8,816.14 km).
How far is Czersk Pomorski from Susanville
Czersk Pomorski is located in Chojnicki, Poland within 53° 47' 34.08" N 17° 58' 26.04" E (53.7928, 17.9739) coordinates. The local time in Czersk Pomorski is 05:54 (19.08.2025)
Susanville is located in California, United States within 40° 25' 14.16" N -121° 23' 12.48" W (40.4206, -120.6132) coordinates. The local time in Susanville is 20:54 (18.08.2025)
The calculated flying distance from Susanville to Susanville is 5,478.10 miles which is equal to 8,816.14 km.
Czersk Pomorski, Chojnicki, Poland
Related Distances from Czersk Pomorski
Susanville, California, United States