Distance from Crossville to Sint-Martens-Lennik
The shortest distance (air line) between Crossville and Sint-Martens-Lennik is 4,315.83 mi (6,945.66 km).
How far is Crossville from Sint-Martens-Lennik
Crossville is located in Tennessee, United States within 35° 57' 9.36" N -86° 58' 13.8" W (35.9526, -85.0295) coordinates. The local time in Crossville is 05:15 (30.07.2025)
Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 12:15 (30.07.2025)
The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 4,315.83 miles which is equal to 6,945.66 km.
Crossville, Tennessee, United States
Related Distances from Crossville
Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium