Distance from Cranston to Boleslawiec
The shortest distance (air line) between Cranston and Boleslawiec is 3,943.27 mi (6,346.07 km).
How far is Cranston from Boleslawiec
Cranston is located in Rhode Island, United States within 41° 45' 56.88" N -72° 30' 51.12" W (41.7658, -71.4858) coordinates. The local time in Cranston is 21:19 (02.09.2025)
Boleslawiec is located in Jeleniogórski, Poland within 51° 16' 0.12" N 15° 34' 0.12" E (51.2667, 15.5667) coordinates. The local time in Boleslawiec is 03:19 (03.09.2025)
The calculated flying distance from Boleslawiec to Boleslawiec is 3,943.27 miles which is equal to 6,346.07 km.
Cranston, Rhode Island, United States
Related Distances from Cranston
Boleslawiec, Jeleniogórski, Poland