Distance from Cranston to Aleksandrow Lodzki
The shortest distance (air line) between Cranston and Aleksandrow Lodzki is 4,066.35 mi (6,544.16 km).
How far is Cranston from Aleksandrow Lodzki
Cranston is located in Rhode Island, United States within 41° 45' 56.88" N -72° 30' 51.12" W (41.7658, -71.4858) coordinates. The local time in Cranston is 14:40 (03.09.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:40 (03.09.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,066.35 miles which is equal to 6,544.16 km.
Cranston, Rhode Island, United States
Related Distances from Cranston
Aleksandrow Lodzki, Łódzki, Poland