Distance from Cornelius to Six-Fours-les-Plages
The shortest distance (air line) between Cornelius and Six-Fours-les-Plages is 4,455.54 mi (7,170.50 km).
How far is Cornelius from Six-Fours-les-Plages
Cornelius is located in North Carolina, United States within 35° 28' 20.64" N -81° 7' 7.32" W (35.4724, -80.8813) coordinates. The local time in Cornelius is 00:52 (03.08.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 06:52 (03.08.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 4,455.54 miles which is equal to 7,170.50 km.
Cornelius, North Carolina, United States
Related Distances from Cornelius
Six-Fours-les-Plages, Var, France