Distance from Cornelius to Bad Sassendorf
The shortest distance (air line) between Cornelius and Bad Sassendorf is 4,312.35 mi (6,940.06 km).
How far is Cornelius from Bad Sassendorf
Cornelius is located in North Carolina, United States within 35° 28' 20.64" N -81° 7' 7.32" W (35.4724, -80.8813) coordinates. The local time in Cornelius is 23:18 (04.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 05:18 (05.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,312.35 miles which is equal to 6,940.06 km.
Cornelius, North Carolina, United States
Related Distances from Cornelius
Bad Sassendorf, Soest, Germany