Distance from Conisbrough to San Angelo
The shortest distance (air line) between Conisbrough and San Angelo is 4,854.17 mi (7,812.03 km).
How far is Conisbrough from San Angelo
Conisbrough is located in Barnsley; Doncaster and Rotherham, United Kingdom within 53° 28' 44.4" N -2° 46' 22.8" W (53.4790, -1.2270) coordinates. The local time in Conisbrough is 14:24 (18.08.2025)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 08:24 (18.08.2025)
The calculated flying distance from San Angelo to San Angelo is 4,854.17 miles which is equal to 7,812.03 km.
Conisbrough, Barnsley; Doncaster and Rotherham, United Kingdom
Related Distances from Conisbrough
San Angelo, Texas, United States