Distance from Cleveland to San Lazzaro di Savena
The shortest distance (air line) between Cleveland and San Lazzaro di Savena is 4,435.89 mi (7,138.87 km).
How far is Cleveland from San Lazzaro di Savena
Cleveland is located in Ohio, United States within 41° 28' 35.04" N -82° 19' 10.2" W (41.4764, -81.6805) coordinates. The local time in Cleveland is 13:17 (01.09.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 19:17 (01.09.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,435.89 miles which is equal to 7,138.87 km.
Cleveland, Ohio, United States
Related Distances from Cleveland
San Lazzaro di Savena, Bologna, Italy