Distance from Cleveland to Aleksandrow Lodzki
The shortest distance (air line) between Cleveland and Aleksandrow Lodzki is 4,448.34 mi (7,158.91 km).
How far is Cleveland from Aleksandrow Lodzki
Cleveland is located in Ohio, United States within 41° 28' 35.04" N -82° 19' 10.2" W (41.4764, -81.6805) coordinates. The local time in Cleveland is 10:48 (29.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:48 (29.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,448.34 miles which is equal to 7,158.91 km.
Cleveland, Ohio, United States
Related Distances from Cleveland
Aleksandrow Lodzki, Łódzki, Poland