Distance from Citrus Heights to Aleksandrow Lodzki
The shortest distance (air line) between Citrus Heights and Aleksandrow Lodzki is 5,747.53 mi (9,249.76 km).
How far is Citrus Heights from Aleksandrow Lodzki
Citrus Heights is located in California, United States within 38° 41' 41.28" N -122° 42' 43.2" W (38.6948, -121.2880) coordinates. The local time in Citrus Heights is 18:50 (31.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:50 (01.09.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,747.53 miles which is equal to 9,249.76 km.
Citrus Heights, California, United States
Related Distances from Citrus Heights
Aleksandrow Lodzki, Łódzki, Poland