Distance from Citrus Heights to Aleksandrow Kujawski
The shortest distance (air line) between Citrus Heights and Aleksandrow Kujawski is 5,671.43 mi (9,127.29 km).
How far is Citrus Heights from Aleksandrow Kujawski
Citrus Heights is located in California, United States within 38° 41' 41.28" N -122° 42' 43.2" W (38.6948, -121.2880) coordinates. The local time in Citrus Heights is 22:52 (30.08.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 07:52 (31.08.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,671.43 miles which is equal to 9,127.29 km.
Citrus Heights, California, United States
Related Distances from Citrus Heights
Aleksandrow Kujawski, Włocławski, Poland