Distance from Christiansburg to Sint-Andries
The shortest distance (air line) between Christiansburg and Sint-Andries is 4,024.12 mi (6,476.19 km).
How far is Christiansburg from Sint-Andries
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 09:21 (01.08.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 15:21 (01.08.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,024.12 miles which is equal to 6,476.19 km.
Christiansburg, Virginia, United States
Related Distances from Christiansburg
Sint-Andries, Arr. Brugge, Belgium