Distance from Cheney to Aleksandrovac
The shortest distance (air line) between Cheney and Aleksandrovac is 5,666.74 mi (9,119.74 km).
How far is Cheney from Aleksandrovac
Cheney is located in Washington, United States within 47° 29' 24.36" N -118° 25' 15.6" W (47.4901, -117.5790) coordinates. The local time in Cheney is 06:05 (16.07.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 15:05 (16.07.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,666.74 miles which is equal to 9,119.74 km.
Cheney, Washington, United States
Related Distances from Cheney
Aleksandrovac, Rasinska oblast, Serbia