Distance from Chateauneuf-les-Martigues to Sever do Vouga
The shortest distance (air line) between Chateauneuf-les-Martigues and Sever do Vouga is 716.96 mi (1,153.83 km).
How far is Chateauneuf-les-Martigues from Sever do Vouga
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 03:28 (30.08.2025)
Sever do Vouga is located in Região de Aveiro, Portugal within 40° 43' 59.88" N -9° 37' 59.88" W (40.7333, -8.3667) coordinates. The local time in Sever do Vouga is 02:28 (30.08.2025)
The calculated flying distance from Sever do Vouga to Sever do Vouga is 716.96 miles which is equal to 1,153.83 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Sever do Vouga, Região de Aveiro, Portugal