Distance from Chateauneuf-les-Martigues to Santo Andre
The shortest distance (air line) between Chateauneuf-les-Martigues and Santo Andre is 815.10 mi (1,311.78 km).
How far is Chateauneuf-les-Martigues from Santo Andre
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 02:31 (30.08.2025)
Santo Andre is located in Alentejo Litoral, Portugal within 38° 2' 60" N -9° 15' 0" W (38.0500, -8.7500) coordinates. The local time in Santo Andre is 01:31 (30.08.2025)
The calculated flying distance from Santo Andre to Santo Andre is 815.10 miles which is equal to 1,311.78 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Santo Andre, Alentejo Litoral, Portugal