Distance from Chateauneuf-les-Martigues to Sannicolau Mare
The shortest distance (air line) between Chateauneuf-les-Martigues and Sannicolau Mare is 779.30 mi (1,254.16 km).
How far is Chateauneuf-les-Martigues from Sannicolau Mare
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 12:13 (02.09.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 13:13 (02.09.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 779.30 miles which is equal to 1,254.16 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Sannicolau Mare, Timiş, Romania