Distance from Chaska to Aleksandrow Kujawski
The shortest distance (air line) between Chaska and Aleksandrow Kujawski is 4,591.38 mi (7,389.11 km).
How far is Chaska from Aleksandrow Kujawski
Chaska is located in Minnesota, United States within 44° 48' 59.04" N -94° 23' 27.24" W (44.8164, -93.6091) coordinates. The local time in Chaska is 13:25 (20.07.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 20:25 (20.07.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,591.38 miles which is equal to 7,389.11 km.
Chaska, Minnesota, United States
Related Distances from Chaska
Aleksandrow Kujawski, Włocławski, Poland