Distance from Cesson-Sevigne to Aleksandrow Lodzki
The shortest distance (air line) between Cesson-Sevigne and Aleksandrow Lodzki is 959.89 mi (1,544.79 km).
How far is Cesson-Sevigne from Aleksandrow Lodzki
Cesson-Sevigne is located in Ille-et-Vilaine, France within 48° 7' 14.88" N -2° 23' 47.04" W (48.1208, -1.6036) coordinates. The local time in Cesson-Sevigne is 01:14 (25.06.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:14 (25.06.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 959.89 miles which is equal to 1,544.79 km.
Cesson-Sevigne, Ille-et-Vilaine, France
Related Distances from Cesson-Sevigne
Aleksandrow Lodzki, Łódzki, Poland