Distance from Cesky Tesin to Zonnebeke
The shortest distance (air line) between Cesky Tesin and Zonnebeke is 693.30 mi (1,115.76 km).
How far is Cesky Tesin from Zonnebeke
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 09:59 (28.05.2025)
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 09:59 (28.05.2025)
The calculated flying distance from Zonnebeke to Zonnebeke is 693.30 miles which is equal to 1,115.76 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Zonnebeke, Arr. Ieper, Belgium