Distance from Cesky Tesin to Oudenburg
The shortest distance (air line) between Cesky Tesin and Oudenburg is 693.04 mi (1,115.35 km).
How far is Cesky Tesin from Oudenburg
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 08:55 (12.05.2025)
Oudenburg is located in Arr. Oostende, Belgium within 51° 10' 59.88" N 3° 0' 0" E (51.1833, 3.0000) coordinates. The local time in Oudenburg is 08:55 (12.05.2025)
The calculated flying distance from Oudenburg to Oudenburg is 693.04 miles which is equal to 1,115.35 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Oudenburg, Arr. Oostende, Belgium