Distance from Cayce to Aleksandrow Lodzki
The shortest distance (air line) between Cayce and Aleksandrow Lodzki is 4,816.18 mi (7,750.89 km).
How far is Cayce from Aleksandrow Lodzki
Cayce is located in South Carolina, United States within 33° 56' 45.24" N -82° 57' 25.56" W (33.9459, -81.0429) coordinates. The local time in Cayce is 00:44 (21.07.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 06:44 (21.07.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,816.18 miles which is equal to 7,750.89 km.
Cayce, South Carolina, United States
Related Distances from Cayce
Aleksandrow Lodzki, Łódzki, Poland