Distance from Burnsville to Diepenbeek
The shortest distance (air line) between Burnsville and Diepenbeek is 4,241.62 mi (6,826.22 km).
How far is Burnsville from Diepenbeek
Burnsville is located in Minnesota, United States within 44° 45' 53.28" N -94° 43' 14.52" W (44.7648, -93.2793) coordinates. The local time in Burnsville is 02:09 (31.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 09:09 (31.07.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,241.62 miles which is equal to 6,826.22 km.
Burnsville, Minnesota, United States
Related Distances from Burnsville
Diepenbeek, Arr. Hasselt, Belgium