Distance from Bonney Lake to Sveti Ivan Zelina
The shortest distance (air line) between Bonney Lake and Sveti Ivan Zelina is 5,526.65 mi (8,894.29 km).
How far is Bonney Lake from Sveti Ivan Zelina
Bonney Lake is located in Washington, United States within 47° 10' 44.76" N -123° 49' 48" W (47.1791, -122.1700) coordinates. The local time in Bonney Lake is 12:13 (31.07.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 21:13 (31.07.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,526.65 miles which is equal to 8,894.29 km.
Bonney Lake, Washington, United States
Related Distances from Bonney Lake
Sveti Ivan Zelina, Zagrebačka županija, Croatia