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      Distance from Bloomingdale to Sint-Pieters-Leeuw

      The shortest distance (air line) between Bloomingdale and Sint-Pieters-Leeuw is 4,605.39 mi (7,411.65 km).

      How far is Bloomingdale from Sint-Pieters-Leeuw

      Bloomingdale is located in Florida, United States within 27° 52' 42.24" N -83° 44' 15.36" W (27.8784, -82.2624) coordinates. The local time in Bloomingdale is 12:59 (04.06.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 18:59 (04.06.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,605.39 miles which is equal to 7,411.65 km.

      Bloomingdale, Florida, United States

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      Bloomingdale to New York (New York)1,004.11 mi (1,615.96 km)
      Bloomingdale to Queens (New York)1,010.82 mi (1,626.77 km)
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      Bloomingdale to Los Angeles (California)2,171.97 mi (3,495.45 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw