Distance from Beltsville to Drobeta-Turnu Severin
The shortest distance (air line) between Beltsville and Drobeta-Turnu Severin is 4,800.27 mi (7,725.29 km).
How far is Beltsville from Drobeta-Turnu Severin
Beltsville is located in Maryland, United States within 39° 2' 21.84" N -77° 4' 44.04" W (39.0394, -76.9211) coordinates. The local time in Beltsville is 09:28 (19.12.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 16:28 (19.12.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 4,800.27 miles which is equal to 7,725.29 km.
Beltsville, Maryland, United States
Related Distances from Beltsville
Drobeta-Turnu Severin, Mehedinţi, Romania