Distance from Begijnendijk to Sendenhorst
The shortest distance (air line) between Begijnendijk and Sendenhorst is 142.92 mi (230.02 km).
How far is Begijnendijk from Sendenhorst
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 10:45 (13.07.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 10:45 (13.07.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 142.92 miles which is equal to 230.02 km.
Begijnendijk, Arr. Leuven, Belgium
Related Distances from Begijnendijk
Sendenhorst, Warendorf, Germany