Distance from Baldwin to Aleksandrow Kujawski
The shortest distance (air line) between Baldwin and Aleksandrow Kujawski is 4,140.83 mi (6,664.03 km).
How far is Baldwin from Aleksandrow Kujawski
Baldwin is located in New York, United States within 40° 39' 3.96" N -74° 23' 33" W (40.6511, -73.6075) coordinates. The local time in Baldwin is 09:05 (27.08.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 15:05 (27.08.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,140.83 miles which is equal to 6,664.03 km.
Baldwin, New York, United States
Related Distances from Baldwin
Aleksandrow Kujawski, Włocławski, Poland