Distance from Bad Sooden-Allendorf to Diepenbeek
The shortest distance (air line) between Bad Sooden-Allendorf and Diepenbeek is 199.78 mi (321.52 km).
How far is Bad Sooden-Allendorf from Diepenbeek
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 05:58 (07.05.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 05:58 (07.05.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 199.78 miles which is equal to 321.52 km.
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany
Related Distances from Bad Sooden-Allendorf
Diepenbeek, Arr. Hasselt, Belgium