Distance from Bad Sassendorf to Alexandroupoli
The shortest distance (air line) between Bad Sassendorf and Alexandroupoli is 1,119.86 mi (1,802.24 km).
How far is Bad Sassendorf from Alexandroupoli
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 03:51 (01.11.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 04:51 (01.11.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,119.86 miles which is equal to 1,802.24 km.
Bad Sassendorf, Soest, Germany