Distance from Bad Liebenwerda to Six-Fours-les-Plages
The shortest distance (air line) between Bad Liebenwerda and Six-Fours-les-Plages is 680.51 mi (1,095.17 km).
How far is Bad Liebenwerda from Six-Fours-les-Plages
Bad Liebenwerda is located in Elbe-Elster, Germany within 51° 31' 0.12" N 13° 24' 0" E (51.5167, 13.4000) coordinates. The local time in Bad Liebenwerda is 15:55 (17.05.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 15:55 (17.05.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 680.51 miles which is equal to 1,095.17 km.
Bad Liebenwerda, Elbe-Elster, Germany
Related Distances from Bad Liebenwerda
Six-Fours-les-Plages, Var, France