Distance from Austintown to Sint-Genesius-Rode
The shortest distance (air line) between Austintown and Sint-Genesius-Rode is 3,913.89 mi (6,298.80 km).
How far is Austintown from Sint-Genesius-Rode
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 09:08 (09.05.2025)
Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 15:08 (09.05.2025)
The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 3,913.89 miles which is equal to 6,298.80 km.
Austintown, Ohio, United States
Related Distances from Austintown
Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium