Distance from Austintown to Sint-Andries
The shortest distance (air line) between Austintown and Sint-Andries is 3,854.68 mi (6,203.51 km).
How far is Austintown from Sint-Andries
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 11:00 (09.05.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 17:00 (09.05.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,854.68 miles which is equal to 6,203.51 km.
Austintown, Ohio, United States
Related Distances from Austintown
Sint-Andries, Arr. Brugge, Belgium