Distance from Austintown to Etterbeek
The shortest distance (air line) between Austintown and Etterbeek is 3,912.67 mi (6,296.83 km).
How far is Austintown from Etterbeek
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 11:14 (08.05.2025)
Etterbeek is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 49' 59.88" N 4° 22' 59.88" E (50.8333, 4.3833) coordinates. The local time in Etterbeek is 17:14 (08.05.2025)
The calculated flying distance from Etterbeek to Etterbeek is 3,912.67 miles which is equal to 6,296.83 km.
Austintown, Ohio, United States
Related Distances from Austintown
Etterbeek, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium