Distance from Austintown to Diepenbeek
The shortest distance (air line) between Austintown and Diepenbeek is 3,950.86 mi (6,358.29 km).
How far is Austintown from Diepenbeek
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 11:22 (08.05.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 17:22 (08.05.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,950.86 miles which is equal to 6,358.29 km.
Austintown, Ohio, United States
Related Distances from Austintown
Diepenbeek, Arr. Hasselt, Belgium