Distance from Austin to San Leandro
The shortest distance (air line) between Austin and San Leandro is 1,483.44 mi (2,387.37 km).
How far is Austin from San Leandro
Austin is located in Texas, United States within 30° 18' 1.8" N -98° 14' 52.08" W (30.3005, -97.7522) coordinates. The local time in Austin is 01:29 (16.08.2025)
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 23:29 (15.08.2025)
The calculated flying distance from San Leandro to San Leandro is 1,483.44 miles which is equal to 2,387.37 km.
Related Distances from Austin
San Leandro, California, United States