Distance from Austin to Jefferson Valley-Yorktown
The shortest distance (air line) between Austin and Jefferson Valley-Yorktown is 1,535.34 mi (2,470.89 km).
How far is Austin from Jefferson Valley-Yorktown
Austin is located in Texas, United States within 30° 18' 1.8" N -98° 14' 52.08" W (30.3005, -97.7522) coordinates. The local time in Austin is 17:31 (05.08.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 18:31 (05.08.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 1,535.34 miles which is equal to 2,470.89 km.
Related Distances from Austin
Jefferson Valley-Yorktown, New York, United States