Distance from Austin to Jefferson Hills
The shortest distance (air line) between Austin and Jefferson Hills is 1,215.42 mi (1,956.02 km).
How far is Austin from Jefferson Hills
Austin is located in Texas, United States within 30° 18' 1.8" N -98° 14' 52.08" W (30.3005, -97.7522) coordinates. The local time in Austin is 23:39 (05.08.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 00:39 (06.08.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 1,215.42 miles which is equal to 1,956.02 km.
Related Distances from Austin
Jefferson Hills, Pennsylvania, United States