Distance from Auburndale to Sint-Kruis
The shortest distance (air line) between Auburndale and Sint-Kruis is 4,525.30 mi (7,282.76 km).
How far is Auburndale from Sint-Kruis
Auburndale is located in Florida, United States within 28° 5' 46.68" N -82° 11' 55.68" W (28.0963, -81.8012) coordinates. The local time in Auburndale is 11:03 (28.05.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 17:03 (28.05.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,525.30 miles which is equal to 7,282.76 km.
Auburndale, Florida, United States
Related Distances from Auburndale
Sint-Kruis, Arr. Brugge, Belgium