Distance from Asbury Park to Sveti Ivan Zelina
The shortest distance (air line) between Asbury Park and Sveti Ivan Zelina is 4,317.92 mi (6,949.02 km).
How far is Asbury Park from Sveti Ivan Zelina
Asbury Park is located in New Jersey, United States within 40° 13' 21.36" N -75° 59' 17.16" W (40.2226, -74.0119) coordinates. The local time in Asbury Park is 19:00 (31.07.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 01:00 (01.08.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,317.92 miles which is equal to 6,949.02 km.
Asbury Park, New Jersey, United States
Related Distances from Asbury Park
Sveti Ivan Zelina, Zagrebačka županija, Croatia