Distance from Arvin to Bad Segeberg
The shortest distance (air line) between Arvin and Bad Segeberg is 5,574.51 mi (8,971.30 km).
How far is Arvin from Bad Segeberg
Arvin is located in California, United States within 35° 11' 39.84" N -119° 10' 9.84" W (35.1944, -118.8306) coordinates. The local time in Arvin is 04:07 (11.08.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 13:07 (11.08.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 5,574.51 miles which is equal to 8,971.30 km.
Arvin, California, United States
Related Distances from Arvin
Bad Segeberg, Segeberg, Germany