Distance from Amherst to Montceau-les-Mines
The shortest distance (air line) between Amherst and Montceau-les-Mines is 4,092.47 mi (6,586.19 km).
How far is Amherst from Montceau-les-Mines
Amherst is located in Ohio, United States within 41° 24' 7.92" N -83° 46' 10.92" W (41.4022, -82.2303) coordinates. The local time in Amherst is 13:06 (03.08.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 19:06 (03.08.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,092.47 miles which is equal to 6,586.19 km.
Related Distances from Amherst
Montceau-les-Mines, Saône-et-Loire, France