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      Distance from Altus to San Vicente de Castellet

      The shortest distance (air line) between Altus and San Vicente de Castellet is 5,181.30 mi (8,338.50 km).

      How far is Altus from San Vicente de Castellet

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 03:08 (25.08.2025)

      San Vicente de Castellet is located in Barcelona, Spain within 41° 39' 55.8" N 1° 51' 50.76" E (41.6655, 1.8641) coordinates. The local time in San Vicente de Castellet is 10:08 (25.08.2025)

      The calculated flying distance from San Vicente de Castellet to San Vicente de Castellet is 5,181.30 miles which is equal to 8,338.50 km.

      Altus, Oklahoma, United States

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      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
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      Altus to Queens (New York)1,450.68 mi (2,334.64 km)
      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
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      San Vicente de Castellet, Barcelona, Spain

      Related Distances to San Vicente de Castellet