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      Distance from Altus to San Fernando de Henares

      The shortest distance (air line) between Altus and San Fernando de Henares is 4,988.15 mi (8,027.66 km).

      How far is Altus from San Fernando de Henares

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 03:38 (25.08.2025)

      San Fernando de Henares is located in Madrid, Spain within 40° 25' 32.16" N -4° 27' 52.92" W (40.4256, -3.5353) coordinates. The local time in San Fernando de Henares is 10:38 (25.08.2025)

      The calculated flying distance from San Fernando de Henares to San Fernando de Henares is 4,988.15 miles which is equal to 8,027.66 km.

      Altus, Oklahoma, United States

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      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
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      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
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      San Fernando de Henares, Madrid, Spain

      Related Distances to San Fernando de Henares