Distance from Altus to Nieuw-Lekkerland
The shortest distance (air line) between Altus and Nieuw-Lekkerland is 4,909.48 mi (7,901.04 km).
How far is Altus from Nieuw-Lekkerland
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 13:24 (16.08.2025)
Nieuw-Lekkerland is located in Zuidoost-Zuid-Holland, Netherlands within 51° 52' 59.88" N 4° 40' 59.88" E (51.8833, 4.6833) coordinates. The local time in Nieuw-Lekkerland is 20:24 (16.08.2025)
The calculated flying distance from Nieuw-Lekkerland to Nieuw-Lekkerland is 4,909.48 miles which is equal to 7,901.04 km.
Altus, Oklahoma, United States
Related Distances from Altus
Nieuw-Lekkerland, Zuidoost-Zuid-Holland, Netherlands